LOOP SEQUENCE NUMBERS IN MAXSCRIPT

eArr=#()
arr = #(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
for i=1 to arr.count do 
(
	local temp=#()	
	local txt= "y"+"["+(i as string)+"]="
	
	if i == 1 then 
		(
			txt+="x"+"["+(i as string)+"]"
		)
	else 
		(
			for y=1 to i  do 
			(
				txt+="x"+"["+(y as string)+"]"
				if y==i do continue
				txt+="+"
			)
		)
	
	append temp #(txt)
	join eArr temp
)

eArr

--#(#("y[1]=x[1]"), #("y[2]=x[1]+x[2]"), #("y[3]=x[1]+x[2]+x[3]"), #("y[4]=x[1]+x[2]+x[3]+x[4]"), #("y[5]=x[1]+x[2]+x[3]+x[4]+x[5]"), #("y[6]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]"), #("y[7]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]"), #("y[8]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]+x[8]"), #("y[9]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]+x[8]+x[9]"), #("y[10]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]+x[8]+x[9]+x[10]"))

thats the formula... you could convert it to array of number (result) too with little tweak

here u go

fn NewArr a b:#() = (
	for i = 1 to a.count do (
		b[i] = 0
		b[i] = for j = 1 to i collect b[i] += a[j]
	)
	b
)

a = #(1,2,3,4,5)
b = NewArr a
	
print b